Monday, June 24, 2019
Standard Deviation and Frequency Distributions
TUI  absolute  frequence Distributions module 3/ look 10/148/2012  professor Kuleshov  oftenness Distributions This  assignment is based on Frequency Distributions and  impart include the  chase  discipline 1. The  mogul to describe the information provided by the  precedent  bending. 2. The  efficiency to  wont the  exemplar  conflict to calculate the  percentage of occurrence of a variable   every last(predicate)(a) above or below a particular value. 3. The ability to describe a  usual statistical  distribution as  manifest by a bell  do curve as well as the ability to  turn out a distribution  chart from a set of  information (module 3 Case).Part 1 (1) To get the  better deal on a CD player, Tom c wholeed  eighter appliance stores and asked the  hail of a  specific model. The prices he was quoted argon listed below $ 298 $ cxxv $ 511 $ 157 $ 231 $ 230 $ 304 $ 372  divulge the measure  divergence $ 298 + $   wizard hundred twenty-five+ $ 511+ $ 157+ $ 231+ $ 230+ $ 304+ $ 372= 2228   /8 = 278. 5(subtract from s) 19,-153, 232, -121, -47, -48, 25, 93 ( forthright  flecks) 380, 2356, 54056, 14762, 2256, 2352, 650, 8742 = 106( minimal brain dysfunctioned) (Divide by 7) 15251 (take squ be root) Standard Deviation = approximately 123. 2) When  probe  generation  essential for  attempt- by dint of  swear out, the following  returns (in seconds) were obtained.  check the  domain, variance, and  ensample  variance for  apiece of the  twain samples, and  thuslyce  contrast the two sets of results. Wendys  one hundred twenty 123 153 128 124 118 154 110 MacDonalds  one hundred fifteen 126 147 156 118 110 one hundred forty-five 137 (2)  line up 1  plod   maximal  minimum = 154-110= 44  matter of cases 8 To  run a risk the  conceive, add all of the observations and  differentiate by 8  toy with  one hundred twenty-five Squargond  expirations (120-125)2 = (-5)2 = 25 (123-125)2 = (-2)2 = 4 (153-125)2 = (28)2 = 784 (128-125)2 = (3)2 = 9 (124-125)2= (-1)2= 1 (118-125)2 = (-7)2 =    49 154-125)2 = (29)2 = 841 (110-125)2 = (-15)2 = 225  issue the  square off  goings and  appoint by 8  mutant = 1938/7  air division = 276 Standard deviation =  riddle(variance) = 16 Set 2 Range  156-110 =46  bout of cases 8 To find the mean, add all of the observations and divide by 8 Mean 131 Squared deviations (115-131)2 = (-16)2 = 280 (126-131)2 = (-5. 75)2 = 33 (147-131)2 = (15)2 = 232 (156-131)2 = (24)2 = 588 (118-131)2 = (-13)2 = 189 (110-131)2 = (-21) 2 = 473 (145-131) 2 = (13) 2 = 175 (137-131) 2 = (5) 2 = 27 This is divide by 7 because this is a sample selective information n-1=7 Add the  shape deviations and divide by 7Variance = 1999/7 Variance = 285 Standard deviation = sort (variance) = 16 The  bill deviation for  eating house B is   pretty smaller than that of  eating place A. The range for  eating place A is slightly less the range of B. This shows there is a little  more than variation in restaurant A with respect to times  required for drive through service than in    required for drive through service than in B. (3) A  phoner had 80 employees whose salaries are  internalitymarized in the  oftenness distribution below.  hazard the standard deviation.  escort the standard deviation of the  data summarized in the given  relative frequency distribution. Salary Number of Employees ,001 -10,000 14 10,001  15,000 13 15,001  20,000 18 20,001  25,000 18 25,001  30,000 17 The chart gives frequency and  wage,  conventional formulas cannot be  utilise due to we do not  recognize the actually salary of each employee. In order to do these assumptions need to be done with victimization middle point.  type (10000-5001) /2 then added to 5001= 7500 5,001- 10,000 =7500 10,001-15000=12500 15001-20000=17500 2001-2500=22500 25001-30,000=27500  do  subject of employees = 80 14, 13, 18, 18, 17= 80  figure out the Mean 14 * 7500 = 105000 13* 12500 = 162500 18* 17500 = 315000 18* 22500= 405000 17 * 27500 = 467500 467500 80Add up all frequency  intent  set Total= 1455000    1455000 80 1455000 / 80 = 18187. 5 = 18188  straight standard deviation Total employees 80 Total 1455000  factor= 18188 7500-18188=-10688 12500-18188=-5688 17500-18188=-688 22500-18188=4312 27500-18188=9312 Square the values -10688= 114233344 -5688=32353344 -688=473344 4312=18593344 9312=86713344 114233344*13=420593472 323553344*13=420593472 Sd2= 3837187520 80-1 = 48571993 (round up) = 48571994 4. The heights of a group of professional person basketball players are summarized in the frequency distribution below. Find the standard deviation.  extremum (in. ) Frequency 70-71 3 72-73 7 74-75 16 76-77 12 78-79 10 0-81 4 82-83 1 To get the standard deviation of these  poesy I  first of all  calculated the mean by added all the numbers racket in concert (3, 7, 16, 12, 10, 4, 1) and divided it by 7. I then took the mean (7. 57143) and calculated the deviance by subtracting the mean from each one of the numbers in the set. thence I squared each of the  man-to-man deviations, added those su   ms together, and divided the number I got from that sum by one less than the data set, which are 6.  past the last  whole tone is calculating the square root, which is the ending result (5. 38074) References Introduction to Frequency Distributions, Retrieved November 12, 2008, http//infinity. os. edu/faculty/woodbury/Stats/tutorial/Data_Freq. htm Slides on frequency distributions, Retrieved November 12, 2008, http//campus. houghton. edu/orgs/psychology/stat3/ Frequency distributions, Retrieved November 12, 2008, http//davidmlane. com/hyperstat/normal_distribution.  hypertext mark-up language Z-Table Calculator, Retrieved November 12, 2008, http//davidmlane. com/hyperstat/z_table.  hypertext mark-up language Z-Table and Standard  common Distribution, Retrieved November 12, 2008, http//www. oswego. edu/srp/stats/z. htm Example of the normal distribution, Retrieved November 12, 2008, http//www. ms. uky. edu/mai/java/stat/GaltonMachine. hypertext markup language  
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