Monday, June 24, 2019

Standard Deviation and Frequency Distributions

TUI absolute frequence Distributions module 3/ look 10/148/2012 professor Kuleshov oftenness Distributions This assignment is based on Frequency Distributions and impart include the chase discipline 1. The mogul to describe the information provided by the precedent bending. 2. The efficiency to wont the exemplar conflict to calculate the percentage of occurrence of a variable every last(predicate)(a) above or below a particular value. 3. The ability to describe a usual statistical distribution as manifest by a bell do curve as well as the ability to turn out a distribution chart from a set of information (module 3 Case).Part 1 (1) To get the better deal on a CD player, Tom c wholeed eighter appliance stores and asked the hail of a specific model. The prices he was quoted argon listed below $ 298 $ cxxv $ 511 $ 157 $ 231 $ 230 $ 304 $ 372 divulge the measure divergence $ 298 + $ wizard hundred twenty-five+ $ 511+ $ 157+ $ 231+ $ 230+ $ 304+ $ 372= 2228 /8 = 278. 5(subtract from s) 19,-153, 232, -121, -47, -48, 25, 93 ( forthright flecks) 380, 2356, 54056, 14762, 2256, 2352, 650, 8742 = 106( minimal brain dysfunctioned) (Divide by 7) 15251 (take squ be root) Standard Deviation = approximately 123. 2) When probe generation essential for attempt- by dint of swear out, the following returns (in seconds) were obtained. check the domain, variance, and ensample variance for apiece of the twain samples, and thuslyce contrast the two sets of results. Wendys one hundred twenty 123 153 128 124 118 154 110 MacDonalds one hundred fifteen 126 147 156 118 110 one hundred forty-five 137 (2) line up 1 plod maximal minimum = 154-110= 44 matter of cases 8 To run a risk the conceive, add all of the observations and differentiate by 8 toy with one hundred twenty-five Squargond expirations (120-125)2 = (-5)2 = 25 (123-125)2 = (-2)2 = 4 (153-125)2 = (28)2 = 784 (128-125)2 = (3)2 = 9 (124-125)2= (-1)2= 1 (118-125)2 = (-7)2 = 49 154-125)2 = (29)2 = 841 (110-125)2 = (-15)2 = 225 issue the square off goings and appoint by 8 mutant = 1938/7 air division = 276 Standard deviation = riddle(variance) = 16 Set 2 Range 156-110 =46 bout of cases 8 To find the mean, add all of the observations and divide by 8 Mean 131 Squared deviations (115-131)2 = (-16)2 = 280 (126-131)2 = (-5. 75)2 = 33 (147-131)2 = (15)2 = 232 (156-131)2 = (24)2 = 588 (118-131)2 = (-13)2 = 189 (110-131)2 = (-21) 2 = 473 (145-131) 2 = (13) 2 = 175 (137-131) 2 = (5) 2 = 27 This is divide by 7 because this is a sample selective information n-1=7 Add the shape deviations and divide by 7Variance = 1999/7 Variance = 285 Standard deviation = sort (variance) = 16 The bill deviation for eating house B is pretty smaller than that of eating place A. The range for eating place A is slightly less the range of B. This shows there is a little more than variation in restaurant A with respect to times required for drive through service than in required for drive through service than in B. (3) A phoner had 80 employees whose salaries are internalitymarized in the oftenness distribution below. hazard the standard deviation. escort the standard deviation of the data summarized in the given relative frequency distribution. Salary Number of Employees ,001 -10,000 14 10,001 15,000 13 15,001 20,000 18 20,001 25,000 18 25,001 30,000 17 The chart gives frequency and wage, conventional formulas cannot be utilise due to we do not recognize the actually salary of each employee. In order to do these assumptions need to be done with victimization middle point. type (10000-5001) /2 then added to 5001= 7500 5,001- 10,000 =7500 10,001-15000=12500 15001-20000=17500 2001-2500=22500 25001-30,000=27500 do subject of employees = 80 14, 13, 18, 18, 17= 80 figure out the Mean 14 * 7500 = 105000 13* 12500 = 162500 18* 17500 = 315000 18* 22500= 405000 17 * 27500 = 467500 467500 80Add up all frequency intent set Total= 1455000 1455000 80 1455000 / 80 = 18187. 5 = 18188 straight standard deviation Total employees 80 Total 1455000 factor= 18188 7500-18188=-10688 12500-18188=-5688 17500-18188=-688 22500-18188=4312 27500-18188=9312 Square the values -10688= 114233344 -5688=32353344 -688=473344 4312=18593344 9312=86713344 114233344*13=420593472 323553344*13=420593472 Sd2= 3837187520 80-1 = 48571993 (round up) = 48571994 4. The heights of a group of professional person basketball players are summarized in the frequency distribution below. Find the standard deviation. extremum (in. ) Frequency 70-71 3 72-73 7 74-75 16 76-77 12 78-79 10 0-81 4 82-83 1 To get the standard deviation of these poesy I first of all calculated the mean by added all the numbers racket in concert (3, 7, 16, 12, 10, 4, 1) and divided it by 7. I then took the mean (7. 57143) and calculated the deviance by subtracting the mean from each one of the numbers in the set. thence I squared each of the man-to-man deviations, added those su ms together, and divided the number I got from that sum by one less than the data set, which are 6. past the last whole tone is calculating the square root, which is the ending result (5. 38074) References Introduction to Frequency Distributions, Retrieved November 12, 2008, http//infinity. os. edu/faculty/woodbury/Stats/tutorial/Data_Freq. htm Slides on frequency distributions, Retrieved November 12, 2008, http//campus. houghton. edu/orgs/psychology/stat3/ Frequency distributions, Retrieved November 12, 2008, http//davidmlane. com/hyperstat/normal_distribution. hypertext mark-up language Z-Table Calculator, Retrieved November 12, 2008, http//davidmlane. com/hyperstat/z_table. hypertext mark-up language Z-Table and Standard common Distribution, Retrieved November 12, 2008, http//www. oswego. edu/srp/stats/z. htm Example of the normal distribution, Retrieved November 12, 2008, http//www. ms. uky. edu/mai/java/stat/GaltonMachine. hypertext markup language

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